Completing a sample easy challenge from Hackerrank

Challenge:

Write a function called countUp(start) that takes a number (start) and counts upwards 10 times with all the words separated by “then”.

For example:

countUp(10);

>> 11 then 12 then 13 then 14 then 15 then 16 then 17 then 18 then 19 then 20

The Solution:

function countUp(start) { start = start + 1; var string = ""; process.stdout.write((start) + string); for (var i = start+1; i < (start + 10); i++) { string = process.stdout.write(" then " + i); } }

`process.stdout.write `

is equivalent to Ruby’s ‘print’ . It removes the line break.

This was a really hard coding challenge, even though it was labeled ‘Easy’.

I knew I had to print out numbers in sequence, incrementing by 1 so I decided to use a ‘for’ loop. Getting all the numbers to print out and then adding ” then ” to the end was easy. Removing the last ” then ” was hard.

I first was trying to loop adding ” then ” after the number like this:

`4 then 5 then 6 then 7 then 8 then`

But then my answer ends with the word ” then ” and that’s incorrect. So nextÂ I tried to just count up to 9 numbers and add the 10th number to the end of the string, but I kept getting an error. After much time had passed, I added ” then ” before the number so that my loop looked like this:

`then 5 then 6 then 7 then 8`

Finally, I added the ‘start’ value +1 to the beginning of the string to pass the tests.

`4 then 5 then 6 then 7 then 8`